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authorMichael J. Chudobiak <mjc@avtechpulse.com>2012-10-11 08:00:10 -0400
committerMichael J. Chudobiak <mjc@avtechpulse.com>2012-10-11 08:00:10 -0400
commit26fbe0556b9260c29ac1aa082d7ce3baacadb665 (patch)
tree9c34f1c726eb43bb6e5dd85fb05f8656f5cc355d
parent7cb7a17dba90fd122a9bea60cc5212140b029e5f (diff)
ignore second newline if 2 are received in rapid succession
-rw-r--r--instr-client.c40
1 files changed, 40 insertions, 0 deletions
diff --git a/instr-client.c b/instr-client.c
index 4106852..8a62f13 100644
--- a/instr-client.c
+++ b/instr-client.c
@@ -3,6 +3,7 @@
#include <string.h>
#include <stdlib.h>
#include <strings.h>
+#include <sys/time.h>
#include "response.h"
#include "version.h"
@@ -45,6 +46,8 @@ static gboolean Matches(char *src, char* dst, gssize size)
return TRUE;
}
+#define TIMEOUT 100000 // 100000 useconds, 100ms
+#define ONESECONDINUSEC 1000000
//GIOChannel callback
static gboolean
@@ -57,6 +60,43 @@ stdinAvailable (GIOChannel *source, GIOCondition condition, gpointer data)
return TRUE;
}
+ // Ignore second \n if two are sent in rapid succession.
+ // This happens when the serial input is terminated with \r\n,
+ // which getty translates to \n\n. The IO handler splits this
+ // into 2 input lines, so we can't use a simple regex to
+ // replace it.
+
+ static struct timeval last = { 0, 0 }; // the time this last ran
+ static struct timeval now; // the time now
+ gettimeofday(&now, NULL );
+
+ if (last.tv_sec != 0) { // shouldn't be zero if we have been in here before
+ if (strcmp(tmp, "\n") == 0) { // is this a newline all on it's own?
+ if (last.tv_sec == now.tv_sec) {
+ // if we're in the same second we can just check the usec field
+ if (now.tv_usec - last.tv_usec < TIMEOUT) {
+ // ignore this \n
+ return TRUE;
+ }
+ }
+ // - check that last and now sec fields are only one second apart
+ // - check that the time elapsed in this second is smaller than the
+ // timeout, if it isn't we don't need to check the other second
+ // - check that there is less of the last second remaining than the timeout
+ else if (now.tv_sec - last.tv_sec == 1 && now.tv_usec < TIMEOUT && (ONESECONDINUSEC - last.tv_usec) < TIMEOUT) {
+ // and then check the the time left in the last second
+ // plus the time in this second is less than the timeout
+ if ((ONESECONDINUSEC - last.tv_usec) + now.tv_usec < TIMEOUT) {
+ // ignore this \n
+ return TRUE;
+ }
+ }
+ }
+ }
+
+ last = now;
+
+
//test if we have an exit word
int idx=0;
for(idx=0; idx<sizeof(exitTokens)/sizeof(exitTokens[0]); idx++) {